16^x(1/32)^-x=4^(-3x+1)

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Solution for 16^x(1/32)^-x=4^(-3x+1) equation: 



16^x(1/32)^-x=4^(-3x+1)

We move all terms to the left:

16^x(1/32)^-x-(4^(-3x+1))=0

We add all the numbers together, and all the variables

16^x(+1/32)^-x-(4^(-3x+1))=0

We add all the numbers together, and all the variables

-1x+16^x(+1/32)^-(4^(-3x+1))=0

We multiply all the terms by the denominator


-1x*32)^+16^x(-((4^(-3x+1)))*32)^+1=0

Wy multiply elements

-32x^2-((4^(-3x+1)))*32)^+1=0

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